2200uF/400v + 2200uF/400v = 4400uF/400v.
You can't add the voltage. Only the capacitance.
From top to bottom you get 4400/2=2200uf at 800v
It is a way of achieving 2200uF at double the voltage rating on cap.
The time constant for the discharge is around 3 seconds.
The RC network across the diode is to protect it during the reverse recovery time of diode, which indicates it is being used to snub inductive spikes having both positive and negative polarity.
During reverse recovery time, (as the voltage on the diode is reversed), the diode looks like a short circuit.
The RC limits the reverse recovery spike current, by bypassing it and dissipating in the 3.6 ohm resistor (11/3=3.6)
It looks like a circuit to catch and discharge high energy inductive spike as used in traction equipment.
An instance of this is a line inductor in series with a pantograph, to 600vDC overhead.
When the pantograph bounces off the overhead, the energy still stored in the line inductor dissipates in this circuit.
It is more likely for the above purpose, and would depend on you regeneration problems as to what you really need.
It is a 2 terminal device that is used on a DC line filter inductor.
Use the parts, maybe, but in it's present form not much good for other than it's intended use.
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