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IndustryArena Forum > MetalWorking Machines > Fadal > fadal facing programming example
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  1. #1
    Join Date
    Sep 2010
    Posts
    11

    Unhappy fadal facing programming example

    hi

    i newly join compnay and making part programming with using fadal controller.
    here i would like face 50*50 block
    i am making program
    m92 z250
    G0 X30 Y0 Z5
    G1 Z-1 F500
    X-150
    Z-2
    X30
    Z-3
    X-150
    CONTINU UP TO 30 MM(FACING UP TO 30MM)

    IF I AM MAKING LIKE THIS IT WILL TAKE MORE TIME TO WRITE LINES
    IF I WANT REPEAT SAME X AND Y AND Z SHOULD GO 1 MM DOWN UP TO 30 MM

    MAY BE I HAVE TO USE SUB PRG FOR THIS
    BUT I DONT KNOW I ABOUT SUB PRG
    PLEASE ANYBODY SEND ME CORRECT FORMAT HOW TO REPAET PROGRAMME.

    THANKING U

    CHINTAN

  2. #2
    Join Date
    Jul 2008
    Posts
    21
    Hi Chintan,

    I would use a sub like this:

    %
    L100
    G1G91Z-1F500
    G90X-150
    G91Z-1
    G90X30
    M17
    M30
    G0G90
    M6T1
    E1X30Y0
    H1Z5
    G1Z0F500M8
    L114
    G0G90Z5M5M9
    G49Z0
    E0X0Y0
    M2
    %

    JB

  3. #3
    Join Date
    Nov 2006
    Posts
    227
    L100
    Z-1 F500
    X-180 /(G91 call will move from X30 to X-150)
    Z-2
    X180 /(X-150 to X30)
    M17
    M30
    G0 G40 G90
    /(need to call tool here)
    /(need to call RPM and start it)
    G0 X30 Y0 Z5
    G91
    L115 (CALL SUB 15 TIMES to go 30- SUB REMOVES 2 EACH LOOP)
    G90 /(out of incremental- back to absolute)
    G0 Z5 (BACK TO ORIGINAL Z)
    /(turn off spindle/coolant)
    G53 X0 Y0 Z0 (OR WHERE EVER YOU WANT TO END UP)
    M02

    This will only go to a depth of 25 as the start point is Z5. Each loop of the sub will remove 2 (Z-1 each way). If you need to remove 30, Z start would be 0 (top of part)

  4. #4
    Join Date
    Sep 2010
    Posts
    11

    Smile thank you

    Quote Originally Posted by jbexplorer View Post
    Hi Chintan,

    I would use a sub like this:

    %
    L100
    G1G91Z-1F500
    G90X-150
    G91Z-1
    G90X30
    M17
    M30
    G0G90
    M6T1
    E1X30Y0
    H1Z5
    G1Z0F500M8
    L114
    G0G90Z5M5M9
    G49Z0
    E0X0Y0
    M2
    %

    JB

    thank you very much

  5. #5
    Join Date
    Sep 2010
    Posts
    11

    Smile thanx

    Quote Originally Posted by JEST View Post
    L100
    Z-1 F500
    X-180 /(G91 call will move from X30 to X-150)
    Z-2
    X180 /(X-150 to X30)
    M17
    M30
    G0 G40 G90
    /(need to call tool here)
    /(need to call RPM and start it)
    G0 X30 Y0 Z5
    G91
    L115 (CALL SUB 15 TIMES to go 30- SUB REMOVES 2 EACH LOOP)
    G90 /(out of incremental- back to absolute)
    G0 Z5 (BACK TO ORIGINAL Z)
    /(turn off spindle/coolant)
    G53 X0 Y0 Z0 (OR WHERE EVER YOU WANT TO END UP)
    M02

    This will only go to a depth of 25 as the start point is Z5. Each loop of the sub will remove 2 (Z-1 each way). If you need to remove 30, Z start would be 0 (top of part)
    thank you very much

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